logx^2-4x=1

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Solution for logx^2-4x=1 equation:


Simplifying
logx2 + -4x = 1

Solving
glox2 + -4x = 1

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '4x' to each side of the equation.
glox2 + -4x + 4x = 1 + 4x

Combine like terms: -4x + 4x = 0
glox2 + 0 = 1 + 4x
glox2 = 1 + 4x

Divide each side by 'lox2'.
g = l-1o-1x-2 + 4l-1o-1x-1

Simplifying
g = l-1o-1x-2 + 4l-1o-1x-1

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